Ask Question
26 June, 21:56

The net electric flux through a cubic box with sides that are 22.0 cm long is 4.90 * 10 3 N ⋅ m 2 / C 4.90*103 N⋅m2/C. What charge Q is enclosed by the box?

+3
Answers (1)
  1. 27 June, 01:53
    0
    Q = 43.4 nC

    Explanation:

    According to the Gauss Law, the net electric flux through a closed surface, is equal to the charge enclosed by this surface, divided by the permitivitty of the free space, as follows:

    Flux = Q/ε₀

    If we know that the net electric flux through a cubic box with sides that are 22 cm. long, is 4.9*10³ N*m²/C, we can find the enclosed charge, defining a gaussian surface identical to this cube, as follows:

    Qenc = 4.9*10³ N*m²/C * 8.85*10⁻¹² C²/N*m² = 43.4*10⁻⁹ C = 43.4 nC
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “The net electric flux through a cubic box with sides that are 22.0 cm long is 4.90 * 10 3 N ⋅ m 2 / C 4.90*103 N⋅m2/C. What charge Q is ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers