Ask Question
31 July, 01:01

Sphere 1 with radius R_1 has positive charge q, Sphere 2 with radius 4.50 R_1 is far from sphere 1 and initially uncharged. The separated spheres are then connected with a wire then uncouth to retain only negligible charge. (a) What is the ratio V_1/V_2 of the final potentials of the spheres? (b) what fraction of q ends up on sphere? (c) What fraction of q ends up on sphere 2? (d) What is the ratio q_1/q_2 of the surface charge densities of the spheres?

+4
Answers (1)
  1. 31 July, 03:50
    0
    capacitance of sphere 2 will be 4.5 times sphere 1

    a) when spheres are in contact they will have same potential finally. So

    V_1 / V_2 = 1

    b)

    Charge will be distributed in the ratio of their capacity

    charge on sphere1 = q x 1 / (1 + 4.5)

    = q / 5.5

    fraction = 1 / 5.5

    c) charge on sphere 2

    = q x 4.5 / 5.5

    fraction = 4.5 / 5.5

    d) surface charge density of sphere 1

    = q / (5.5 x A) where A is surface area

    surface charge density of sphere 2

    = q x 4.5 / (5.5 x 4.5² A) where A is surface area

    = q / (5.5 x 4.5 A)

    q_1/q_2 = 4.5
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Sphere 1 with radius R_1 has positive charge q, Sphere 2 with radius 4.50 R_1 is far from sphere 1 and initially uncharged. The separated ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers