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6 December, 05:45

Assume a beam with stirrups inclined at 60o angle with respect to the longitudinal steel resisting cracks developing at 45o angles. Derive analytically the equation that allows you to calculate the shear resistance provided by the stirrups as a function of the stirrup and crack angle.

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  1. 6 December, 07:11
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    Shear resistance of a inclined stirrup is given by

    Vᵇ = Asb (0.95*Fy) (cos α - sin α*cotβ) ((d-d') / sᵇ)

    Explanation:

    The shear resistance is checked in accordance with BS8110: Part 1, section 3.5.5. Shear resistance of a inclined stirrup is given by

    Vᵇ = Asb (0.95*Fy) (cos α - sin α*cotβ) ((d-d') / sᵇ)

    where,

    Vᵇ=design shear resistance of inclined bars

    Asb=cros-sectional area of the inclined bars

    Fy=characteristics strength of the stirrups

    α=angle between the inclined bars and the axis of the beam

    β=angle between the compression strut of inclined bars and the axis of the beam

    sᵇ=spacing of the inclined bars

    d = effective depth and d'=effective depth minus cover to reinforcement

    The shear stress is given by

    v=V/bd

    where V is the shear force due to ultimate loads. If v is shear stress
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