Ask Question
22 October, 10:58

A 100 gram cylinder of copper initially at temperature of 200 degrees celsius immersed in 400 grams of water which is at 20 degrees celsius. Find the equilibrium temperature of copper and water system? specific heat of copper is 387 J/kg degrees of copper

+2
Answers (1)
  1. 22 October, 11:08
    0
    temperature of water is 24 degree

    temperature of copper is 26.89 degree

    Explanation:

    given data

    copper mass = 100 gram

    temperature = 200 degree

    water mass = 400 gram

    temperature = 20 degree

    specific heat of copper = 387 J/kg = 0.387 J/g

    to find out

    temperature of copper and water

    solution

    we know in equilibrium condition heat is loss by copper is equal to heat is gain by water and we consider here x is temperature so equation is

    mcΔt for copper = mcΔt for water ... 1

    100 (0.387) (200-x) = 400 (4.187) (x-20) ... 2

    solve it and we get x

    x = 24.06

    so here temperature of water is 24 degree

    and put this value in equation 2 for water we get temperature of copper

    100 (0.387) (200-x) = 400 (4.187) (x-20)

    100 (0.387) (200-x) = 400 (4.187) (24-20)

    solve it and we get

    x = 26.89 degree

    so temperature of copper is 26.89 degree
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A 100 gram cylinder of copper initially at temperature of 200 degrees celsius immersed in 400 grams of water which is at 20 degrees ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers