A truck is traveling at 11.9 m/s down a hill when the brakes on all four wheels lock. The hill makes an angle of 15 ° with respect to the horizontal. The coefficient of kinetic friction between the tires and the road is 0.861. How far does the truck skid before coming to a stop?

s = 12.62 m

Explanation:

given,

speed of the truck = 11.9 m/s

angle of inclination = 15 °

coefficient of friction = 0.861

we know,

we know

m a = μ m g cos θ - m g sinθ

a = μ g cos θ - m sinθ

a = 0.861 x 9.8 x cos 15 ° - 9.8 sin15°

a = 5.61 m/s²

we know

v² = u² + 2 a s

final velocity zero

0² = u² - 2 a s

11.9² = 2 x 5.61 x s

s = 12.62 m