When a mass is placed on a spring with a spring constant of 15 newtons per meter, the spring is compressed 0.25 meter. How much elastic potential energy is stored in the spring?

0.47 J

Explanation:

The elastic potential energy of a spring is given as,

E = 1/2ke² ... Equation 1

Where E = Elastic potential energy, k = spring constant, e = extension/compression.

Given: k = 15 N/m, e = 0.25 m.

Substitute into equation 1.

E = 1/2 (15) (0.25) ²

E = 0.46875

E ≈ 0.47 J.

Hence the elastic potential energy stored in the spring = 0.47 J