A football is thrown at an initial velocity of 51 mph at an angle of 37 degrees. How many yards is the football thrown

Answer:250.03m

Explanation:

Initial velocity = u=51mph

Angle=β=37

Acceleration due to gravity=g=10

The distance covered by the football is the range

Range = (u^2xsin2β) / g

Range = (51^2xsin (2x37)) / 10

Range = (51x51xsin74) / 10

Range = (2601xsin74) / 10

Range = (2601x0.9613) / 10

Range = (2500.3) / 10

Range=250.03m