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4 November, 11:51

As a new electrical technician, you are designing a large solenoid to produce a uniform 0.160-T magnetic field near the center of the solenoid. You have enough wire for 4300 circular turns. This solenoid must be 1.10 m long and 3.50 cm in diameter. What current will you need to produce the necessary field?

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  1. 4 November, 12:34
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    Current = 32.6 A

    Explanation:

    Magnetic field = B = 0.160 T

    No. of turns of coil = N = 4300

    Length of the solenoid = L = 1.10 m

    Current required depends on the B, L, N and the magnetic permeability μ₀

    B = μ₀ N I / L

    ⇒ Current = I = B L / μ₀N = (0.160) (1.10) / (4π * 10⁻⁷) (4300)

    = 32.6 A
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