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30 November, 17:42

At 1000°C and a pressure of 1200 mm Hg, a sample of methane occupies 20.0 L. What will be it's temperature if it is compressed to a volume of 4.00 L and a pressure of 3600 mm Hg?

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  1. 30 November, 19:05
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    491°C

    Explanation:

    Ideal gas law:

    PV = nRT

    If n is constant:

    PV / T = PV / T

    (1200 mmHg) (20.0 L) / (1273 K) = (3600 mmHg) (4.00 L) / T

    T = 764 K

    T = 491°C
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