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17 March, 20:10

Energy that is not utilized for work or heat transfer is converted to the chemical energy of body fat containing about 39 kJ/g. How many grams of fat will you gain if you eat 10,000 kJ (about 2500 kcal) one day and do nothing but sit relaxed for 16.0 h and sleep for the other 8.00 h

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  1. 17 March, 22:07
    0
    mass=238.52g

    Explanation:

    Energy that is not utilized for work or heat transfer is converted to the chemical energy of body fat containing about 39 kJ/g. How many grams of fat will you gain if you eat 10,000 kJ (about 2500 kcal) one day and do nothing but sit relaxed for 16.0 h and sleep for the other 8.00 h

    unutilized energy converted to body fat, F=39 kj/g

    time to relax=16h

    consumed energy = 10000 kj

    sleeping time=8h

    rate of energy consumption whilst sleeping=83j/s

    rate of energy consumption whilst sitting=120j/s

    energy is power x time

    E=p*t

    substituting the parameters

    energy used in sleeping=83j/s*8*3600=2390400=2390.4kJ

    energy consumed whilst sitting=120j/s*16*3600=6912kj

    total unused nery = 2390.4kJ+6912kj

    9302.4kj

    energy stored / mass=39 kJ/g

    9302.4kj=39 kJ/g*mass

    mass=9302.4kj/39 kJ/g

    mass=238.52g
  2. 17 March, 23:41
    0
    51.28 grams of fat will gain

    Explanation:

    Correction: 10,000 kj about 2500 cal not 2500 kcal.

    Asumption: basal metabolic rate will depend of weight, lenght, age and gender but its estipulated a 2000 cal basal metabolic rate as a standar for the calculation for nutritional value of food.

    eating a 2500 cal in one day will left

    Consuming about 2,500 calories in a day where you only sit relaxed for 16 hours and the rest of the time was used to sleep will mean a basal metabolism of 2000 cal, so 500 calories were left unused, taking into account that 1 calorie is about 4 kj we have to

    500 cal * 4kj / cal = 2000 kj

    The amount of energy stored as fat will be given by the following equation:

    Unused energy / energy contained in one gram of fat = 2000 kj / (39 kj / g) = 51.28 grams of fat gain
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