Ask Question
30 November, 04:41

A solid conducting sphere with radius R that carries positive charge Q is concentric with a very thin insulating shell of radius 2R that also carries charge Q. The charge Q is distributed uniformly over the insulating shell. Find the magnitude of the electric field in the region 02R. Express your answer in terms of the variables R, r, Q, and constants π and ε0.

+4
Answers (1)
  1. 30 November, 05:34
    0
    Gauss Law relates the distribution of electric charge to the resulting electric field.

    Applying Gauss's Law,

    EA = Q / ε₀

    Where:

    E is the magnitude of the electric field,

    A is the cross-sectional area of the conducting sphere,

    Q is the positive charge

    ε₀ is the permittivity

    We be considering cases for the specified regions.

    Case 1: When r < R

    The electric field is zero, since the enclosed charge is equal to zero

    E (r) = 0

    Case 2: When R < r < 2R

    The enclosed charge equals to Q, then the electric field equals;

    E (4πr²) = Q / ε₀

    E = Q / 4πε₀r²

    E = KQ / r²

    Constant K = 1 / 4πε₀ = 9.0 * 10⁹ Nm²/C²

    Case 3: When r > 2R

    The enclosed charge equals to Q, then the electric field equals;

    E (4πr²) = 2Q / ε₀

    E = 2Q / 4πε₀r²

    E = 2KQ / r²
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A solid conducting sphere with radius R that carries positive charge Q is concentric with a very thin insulating shell of radius 2R that ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers