Calculate the charge due to all of the electrons present in 1.0 mL of pure water. (1 mL of water will contain 3.34 / times 10^{22}3.34*10 22 water molecules).

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Physics

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9 May, 10:29

Calculate the charge due to all of the electrons present in 1.0 mL of pure water. (1 mL of water will contain 3.34 / times 10^{22}3.34*10 22 water molecules).

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Answers (1)

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Janae Perry · Answer 1

4.8 x 10^4 C

Explanation:

number of molecules in 1 ml of water = 3.34 x 10^22

1 molecule of water contains 9 electrons

So, the number of electrons in 1 ml of water = 9 x 3.34 x 10^22

= 30.06 x 10^22

Charge of 1 electron = 1.6 x 10^-19 C

So, the charge on 30.06 x 10^22 electrons = 1.6 x 10^-19 x 30.06 x 10^22

= 4.8 x 10^4 C