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7 October, 10:32

A golf ball is struck with a velocity of 80 ft/s as shown. Determine the speed at which it strikes the ground at b and the time of flight from a to b

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  1. 7 October, 12:46
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    Speed at which it strikes the ground = 67.4ft/s

    Time of flight = 3.57secs

    Explanation:

    (Va) x = 80cos (10+45) ° = 44.886

    (Va) y = 80sin (10+45) ° = 65.532

    S=So + Vot + 1/2at^2

    d sin 10° = 0 + 65.532t + 1/2 (-32.2) t^2

    0.17d = 0 + 65.532t + (-16.1) t^2

    Solving the equation gives

    d=166ft

    t = 3.57seconds

    (Vb) x = (Va) x = 45.886

    (Vb) y = 65.532 - 32.2 (3.57)

    (Vb) y = - 49.357

    Vb = sqrt (45.886^2 + (-49.357^2))

    Vb = 67.4ft/s
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