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19 December, 10:10

Light travels from air (n = 1) into a tank of water (n = 1.33) and continues on into a layer of glass (n = 1.5). The light strikes the air-water interface at θi = 45°. What angle does the beam make to the normal line inside the glass (i. e., θr in the glass) ? A) 20° B) 28° C) 36° D) 44°

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  1. 19 December, 10:59
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    option B is correct

    beam make to the normal line inside the glass angle is 28°

    Explanation:

    Given data

    air (n = 1)

    water (n = 1.33)

    glass (n = 1.5)

    air-water interface at θi = 45°

    to find out

    angle does the beam make to the normal line inside the glass i. e θr

    solution

    we know here in air water interface

    n1 = 1 and angle 45° and n2 = 1.33

    n1*Sin (θ) i = n2*Sin (θ) r ... 1

    so now put all value in equation 1

    1*Sin45 = 1.33 * sin (θ) r

    (θ) r = 32.12°

    so this is here (θ) r refraction angle in the water

    and

    we know this angle act as incident angle for water glass

    so that

    n2*Sin (θ) r = n3*Sin (θ) g ... 2

    here n3 = 1.5 and n2 = 1.33 and (θ) r = 32.12°

    so

    1.33 * Sin 32.12 = 1.5*Sin (θ) g

    (θ) g = 28 degree

    so option B is correct

    beam make to the normal line inside the glass angle is 28°
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