In one cycle, a freezer uses 792 J of electrical energy in order to remove 1765 J of heat from its freezer compartment at 10.0°F. A) What is the coefficient of performance of this freezer?

B) How much heat does it expel into the room during this cycle? (J)

coefficient of performance is 2.22

heat expel into the room during this cycle is 2557 J

Explanation:

Given data

electrical energy w = 792 J

heat Qc = 1765 J

temperature = 10.0°F

to find out

coefficient of performance of this freezer and How much heat does it expel

solution

we know that coefficient of performance calculate by formula that is

coefficient of performance = Qc / W ... 1

put both value we get

coefficient of performance = 1765 / 792

coefficient of performance is 2.22

and

we know heat expel that is calculated by

by heat pump thta is

heat expel = w + Qc ... 2

put here both value we get

heat expel = 1765 + 792

heat expel = 2557

so heat expel into the room during this cycle is 2557 J