A two-slit Fraunhofer interference-diffraction pattern is observed with light of wavelength 672 nm. The slits have widths of 0.03 mm and are separated by 0.24 mm. How many bright fringes will be seen inside the central diffraction maximum?

Question

Physics

Phillip Nixon

6 January, 21:01

A two-slit Fraunhofer interference-diffraction pattern is observed with light of wavelength 672 nm. The slits have widths of 0.03 mm and are separated by 0.24 mm. How many bright fringes will be seen inside the central diffraction maximum?

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Answers (1)

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Devon Middleton · Answer 1

In case of diffraction, angular width of central maxima = 2 λ/d

λ is wave length of light and d is slit width

In case of interference, angular width of each fringe

= λ / D

D is distance between two slits

No of interference fringe in central diffraction fringe

=2 λ/d x D/λ = 2 x D / d = 2 x. 24/.03 = 16.