A bacterium (mass = 2.27 x 10^-15 kg) in the blood is moving at 0.306 m/s. What is the de Broglie wavelength of this bacterium?

The de Broglie wavelength of the bacterium is 9.54*10^-19 m

Explanation:

given the mass m 2.27*10^-15 kg of bacterium and the velocity v = 0.306 m/s that it is moving with in the blood. the momentum of the bacterium is P = m*v and the planck constant h = 6.63*10^-34 m^2*kg/s.

the de Broglie wavelength is given by:

λ = h/P

= h / (m*v)

= (6.63*10^-34) / [ (2.27*10^-15) * (0.306) ]

= 9.54*10^-19 m

Therefore, the de Broglie wavelength of the bacterium is 9.54*10^-19 m.