A particle with a mass of 6.67x10^-27 kg has a de Broglie wavelength of 7.22 pm. What is the particle's speed?

The speed of the particle is 13767.35 m/s.

Explanation:

given the mass m = 6.67*10^-27 kg of particle and moving with a speed v. the momentum of the particle is given by P = m*v and the planck constant h = 6.63*10^-34 m^2*kg/s. the wavelength is λ = 7.22 pm ≈7.22*10^-12 m

The de Broglie wavelength is given by:

λ = h/P

λ = h / (m*v)

v = h/λ*m

= (6.63*10^-34) / [ (7.22*10^-12) * (6.67*10^-27) ]

= 13767.35 m/s

Therefore, the speed of the particle is 13767.35 m/s.