A person's prescription for bifocals is - 0.25 diopter for distant vision and + 2.50 diopters for near vision, the near vision being accomplished by inserts into the distant vision lens. What is the net power of the near vision correction?

net power is + 2.25 D

Explanation:

Given data

distance vision = - 0.25 D

near vision = + 2.50 D

to find out

net power

solution

we have given a person lens power for near is - 0.25 diopter and lens power for near power is + 2.50 diopter so

net power is sum of both the power vision

so

net power = distance + near power

put both value we get net power

net power = (-0.25 D) + ( + 2.50 D)

net power = + 2.25 D

so net power is + 2.25 D