Two 0.2304 cm x 0.2304 cm square aluminum electrodes, spaced 0.5974 mm apart are connected to a 61 V battery. What is the charge on each plate in nanoCoulombs.

The charge on each plate is 0.0048 nC

Explanation:

for the distance between the plates d and given the area of plates, A, and ε = 8.85*10^-12 C^2/N. m^2, the capacitance of the plates is given by:

C = (A*ε) / d

=[ (0.2304*10^-2) (0.2304*10^-2) * (8.85*10^-12)) / (0.5974*10^-3)

= 7.86*10^-14 F

then if the plates are connected to a battery of voltage V = 61 V, the charge on the plates is given by:

q = C*V

= (7.86*10^-14) * (61)

= 4.80*10^-14 C

≈ 0.0048 nC

Therefore, the charge on each plate is 0.0048 nC.