In air an object weighs 15N. when immersed in water it weighs 12N. when immersed in another liquid it weighs 13N. determine the density of d object and that of d other liquid

Its volume displaced 3 Newtons of water

3 Newtons = mass of water * g

g is about 9.81m/s^2

so mass of water = 3/9.81 = 0.306 kg

Water density is about 1000 kg/meter^3

0.306 kg * 10^-3m^3/kg = 3.06 * 10^-4 m^3 volume

so

15 kg/3.06*10^-4 m^3 = 4.9*10^4 kg/m^3

if you want grams/cm^3

4.9*10^4 * 10^-6 m^3/cm^3 * 10^3 g/kg = 49 g/cm^3

Answer: relative density of object=5 relative density of liquid=2/3

Explanation:

Loss of weight in water=15-12=3

Density of object=weight in air:weight in water

Density of object=15:3=5

Density of liquid=upthrust in liquid:upthrust in water

Density of liquid = (15-13) : (15-12) = 2/3