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28 April, 13:01

A 282 kg bumper car moving right at 3.50 m/s collides with a 155 kg bumper car moving 1.8 m/s left. Afterwards, the 282 kg car moves right at 0.800 m/s. What is the momentum of the 155 kg car afterwards? (Unit=kg*m/s)

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Answers (2)
  1. 28 April, 15:39
    0
    482 kg m/s

    Explanation:

    Momentum before = momentum after

    m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂

    (282) (3.50) + (155) (-1.80) = (282) (0.800) + (155) v

    987 - 279 = 225.6 + 155v

    v = 3.11 m/s

    The momentum of the car is:

    p = mv

    p = (155 kg) (3.11 m/s)

    p = 482 kg m/s
  2. 28 April, 15:50
    0
    482.4kgm/s

    Explanation:

    ... 482.4kgm/s
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