Ask Question
1 October, 12:47

An airplane flies due west (i. e. in the-X direction) between two airports. For one-quarter of the distance it travels at 650.0 km/h and the rest at 750.0 km/h. What is the average velocity (not speed) of the airplane?

+3
Answers (1)
  1. 1 October, 16:09
    0
    average velocity 722 km/h

    Explanation:

    The average speed is defined with the total distance traveled between the total time, let's look for distance and time, we can use the equation

    V = X / t

    The first distance tells us that it travels ¼ of the total distance (X) at a speed (V1) of 650 km / h

    V1 = X1 / t1

    t1 = X1 / V1

    t1 = ¼ X / 650

    The second distance runs ¾ of the total distance at V2 = 750 km / h

    V2 = X2 / t2

    t2 = X2 / V2

    t2 = ¾ X / 750

    Total time is the sum of these times

    t all = t1 + t2

    t all = ¼ X / 650 + ¾ X / 750

    t all = X (1/2600 + 3/3000)

    t all = X (1/2600 + 1/1000)

    Let's calculate the average speed

    V = X / t

    V = X / X (1/2600 + 0.001)

    V = 1 / 0.001385

    V = 722 km / h
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “An airplane flies due west (i. e. in the-X direction) between two airports. For one-quarter of the distance it travels at 650.0 km/h and ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers