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18 December, 11:27

Find the magnitude, in joules, of a single quantum of energy in the radio signal broadcast at 1160 kHz on the AM dial. Show your work.

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  1. 18 December, 15:06
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    E = 7.70 * 10⁻²⁸ J

    Explanation:

    Energy = hf

    h = Planck's constant = 6.63 * 10⁻³⁴ J. s

    f = frequency = 1160 KHz = 1.16 * 10⁶ Hz

    E = (6.63 * 10⁻³⁴ * 1.16 * 10⁶)

    E = 7.70 * 10⁻²⁸ J
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