A 0.023 kg golf ball moving at 15.7 m/s crashes through the window of a house in 5.3 * 10-4 s. After the crash, the ball continues in the same direction with a speed of 11.4 m/s. Assuming the force exerted on the ball by the window was constant, what was the magnitude of this force? Answer in units of N.

Question

Physics

Harper Reed

23 April, 09:10

A 0.023 kg golf ball moving at 15.7 m/s crashes through the window of a house in 5.3 * 10-4 s. After the crash, the ball continues in the same direction with a speed of 11.4 m/s. Assuming the force exerted on the ball by the window was constant, what was the magnitude of this force? Answer in units of N.

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Answers (1)

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James Yu · Answer 1

Magnitude of the force exerted on the window = 186.6 N

Explanation:

Impulse = change in momentum

Impulse = force * time period during which it acts = F * t = Ft

Change in momentum = m (v₁ - v₂)

m = 0.023 kg, v₁ = 15.7 m/s, v₂ = 11.4 m/s

Change in momentum = 0.023 (15.7 - 11.4) = 0.0989 kgm/s

Impulse = change in momentum = 0.0989

Ft = 0.0989

t = 5.3 * 10⁻⁴ s = 0.00053

F = 0.0989/0.00053 = 186.6 N