A ball with mass of 0.050 kg is dropped from a height of h1 = 1.5 m. It collides with the floor, then bounces up to a height of h2 = 1.0 m. The Collison takes 0.015 s.

Use part e to Calculate impulse (J) ? Write the formula first.

Use part f to Calculate the average force acting (F) on the ball by the floor during the collision?

*Write the formula

Calculate the change in the kinetic energy (∆K) in the collision. Write formula first.

What happens to the lost kinetic energy?

What type of Collision Is this?

Impulse of reaction force of floor = change in momentum

Velocity of impact = √ 2gh₁

= √ 2 x 9.8 x 1.5 = 5.4 m / s.

velocity of rebound = √2gh₂

= √ 2x 9.8 x 1

= 4.427 m / s.

Initial momentum =.050 x 5.4 =.27 kg m/s

Final momentum =.05 x 4.427 =.22 kg. m/s

change in momentum =.27 -.22 =.05 kg m/s

Impulse =.05 kg m / s

Impulse = force x time

force = impulse / time

.05 /.015 = 3.33 N.

kinetic energy = 1/2 m v²

Initial kinetic energy = 1/2 x. 05 x 5.4²

= 0.729 J

Final Kinetic Energy = 1/2 x. 05 x 4.427²

= 0.489 J

Change in Kinetic energy = 0.24 J

Lost kinetic energy is due to conversion of energy into sound light etc.