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31 August, 18:01

A horizontal wire of length 0.53 m. carrying a current of 7.5 A. is placed in a uniform external magnetic field. When the wire is horizontal, it experiences no magnetic force. When the wire is tilted upward at an angle of 19°, it experiences a magnetic field of 4.4x10^-3N. Determine the magnitude of the external magnetic field.

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  1. 31 August, 21:59
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    3.4 mT

    Explanation:

    L = 0.53 m

    i = 7.5 A

    Theta = 19 degree

    F = 4.4 * 10^-3 N

    Let B be the strength of magnetic field.

    Force on a current carrying conductor placed in a magnetic field.

    F = i * L * B * Sin theta

    4.4 * 10^-3 = 7.5 * 0.53 * B * Sin 19

    B = 3.4 * 10^-3 Tesla

    B = 3.4 mT
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