The latent heat of fusion for water is 33.5 * 10⁴ J/kg, while the latent heat of vaporization is 22.6 * 10⁵ J/kg. What mass m of water at 0 °C must be frozen in order to release the amount of heat that 2.48 kg of steam at 100 °C releases when it condenses?

16.78kg

Explanation:

Data Given from question

Heat of fusion of water Lf=33.5*10^4 J/kg Lf=33.5*10^4 J/kg

Heat of vaporization Lv=22.6*10^5 J/kg Lv=22.6*10^5 J/kg

Mass of the steam condensed Ms=2.48 kgms=2.48 kg

From the condition given in the question

Heat Released during freezing = Heat released during condensation

Where Mw = Mass of water

MwLf=MsLv

MwLf=MsLv

Mw=MsLv:Lf

Mw=MsLv:Lf

Mw=2.48 kg*22.6*10^5 J/KG: 33.4*10^4 J/kg

Mw=2.48 kg*22.6*10^5 J/kg : 33.4*10^4 J/kg

Therefore mass of water would be

Mw=16.78 kg