An electron (charge - 1.6 ' 10 - 19 C) moves on a path perpendicular to the direction of a uniform electric field of strength 3.0 N/C. How much work is done on the electron as it moves 15 cm?

The charge on the electron is

q=1.6*10^-19C

It moves in a path perpendicular to the electric field

Given that the uniform electric field is

E=3N/C.

We need to calculate Work

Distance moved is

d=15cm=0.15m

W=q ∫E. ds

Thus, the angle θ between the path and electric field is 90°, and the dot product E. ds is zero

E. ds = Eds Cos θ = Edscos90

Cos 90=0

Then E. ds=0

Now,

W=q ∫E. ds

W=q * 0

W=0J