Three moles of an ideal gas undergo a reversible isothermal compression at 22.0°C. During this compression, 1700 J of work is done on the gas. What is the change in entropy of the gas? (J/K)

change in entropy is - 5.7627 J/K

Explanation:

Given data

temperature = 22.0°C = 22 + 273 = 295 K

work is done = 1700 J

to find out

change in entropy

solution

we know that change in entropy = Q / T ... 1

from 1st law of thermodynamic we know

Q = W for change in internal energy = 0

Q = - 1700 J

so from equation 1

change in entropy = - 1700 / 295

change in entropy = - 5.7627

so change in entropy is - 5.7627 J/K