A hot air balloon is filled with 1.45 * 10 6 L of an ideal gas on a cool morning (11 ∘ C). The air is heated to 109 ∘ C. What is the volume of the air in the balloon after it is heated?

The volume of air after the balloon is heated = 1.95 * 10⁶ L

Explanation:

Charles Law: Charles' law states that the volume of a given mass of gas is directly proportional to the temperature in Kelvin, provided that the pressure remains constant.

It can be expressed mathematically as,

V₁/T₁ = V₂/T₂

Making V₂ The subject of the equation

V₂ = (V₁/T₁) T₂ ... Equation 1

Where V₁ = Initial Volume, T₁ = Initial Temperature, V₂ = Final Volume, T₂ = final Temperature

Given: V₁ = 1.45 * 10⁶ L, T₁ = 11 °C = (11 + 273) K = 284 K, T₂ = 109 °C = (109 + 273) = 382 K.

Substituting these values into equation 1 above,

V₂ = (1.45*10⁶) 382/284

V₂ = 1.95 * 10⁶ L

Therefore the volume of air after the balloon is heated = 1.95 * 10⁶ L