A copper sphere has a radius of 2.50 m under normal room pressure of 1.0 * 105 N/m2. If we increase the pressure on this sphere to 10 times the normal room pressure, what is the change in its volume? The bulk modulus for copper is 1.4 * 1011 Pa

-4.2081 * 10⁻⁴ m³

Explanation:

Volume of the copper sphere = 4/3 π r³ where r is the radius of the sphere which = 2.50 m

Volume of copper Vo = 4/3 * 3.142 * 2.5³ = 65.46 m³

Bulk modulus = - VoΔp / ΔV where Vo is the initial volume of the sphere, Δp is the change in pressure in N/m² and ΔV is the change in volume

make ΔV subject of the formula

ΔV = - VoΔp / B = (-65.46 * (10 - 1) * 10⁵) / (1.4 * 10¹¹)

ΔV = - 589.14 * 10⁵ / (1.4 * 10 ¹¹) = - 420.81 * 10 ⁻⁶ m³ = - 4.2081 * 10⁻⁴ m³