Ask Question
20 October, 18:48

The average density of the body of a fish is 1080kg/m^3. To keep from sinking, the fish increases its volume by inflating an internal air bladder, known as a swim bladder, with air.

By what percent must the fish increase its volume to be neutrally buoyant in fresh water? Use 1.28kg/m^3 for the density of air at 20 degrees Celsius. (change in V/V)

+4
Answers (1)
  1. 20 October, 19:40
    0
    Increase of volume (F) = 8.01%

    Explanation:

    Given:

    Density of fish = 1,080 kg/m³

    Density of water = 1,000 kg/m³

    density of air = 1.28 kg/m³

    Find:

    Increase of volume (F)

    Computation:

    1,080 kg/m³ + [F * 1.28 kg/m³ ] = (1+F) * 1,000 kg/m³

    1,080 + 1.28 F = 1,000 F + 1,000

    80 = 998.72 F

    F = 0.0801 (Approx)

    F = 8.01% (Approx)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “The average density of the body of a fish is 1080kg/m^3. To keep from sinking, the fish increases its volume by inflating an internal air ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers