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22 May, 12:00

Nearly monochromatic light of wavelength 420 nm is split in two beams. The first beam traveled 105 nm to the screen more than the second beam, thus yielding a path difference of 105 nm. A) Calculate the phase difference between the two beams. The interference pattern of the two beams will be (a) Destructive (b) constructive (c) more information is needed

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  1. 22 May, 13:52
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    phase difference = π / 2

    constructive interference

    Explanation:

    Given data

    wavelength = 420 nm

    1st beam = 105 nm

    path difference = 105 nm

    to find out

    phase difference and interference pattern of the two beams

    solution

    we use here equation of phase difference that is

    phase difference = 2π / wavelength * Δx

    put here value

    phase difference = 2π / 420 * 105

    phase difference = π / 2

    and

    we know that here path difference Δx is the integral multiple of the wavelength so it will be constructive interference

    Δx is wavelength / 4
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