A basketball player is running at a constant speed of 2.5 m/s when he tosses a basketball upward with a speed of 6.0 m/s. How far does the player run before he catches the ball? Ignore air resistance. I got stuck because I wasn't sure wich formula to use when approaching this problem. Does it involve an angle at all?

distance=6.11m

Explanation:

A basketball player is running at a constant speed of 2.5 m/s when he tosses a basketball upward with a speed of 6.0 m/s. How far does the player run before he catches the ball? Ignore air resistance. I got stuck because I wasn't sure which formula to use when approaching this problem. Does it involve an angle at all?

first of all we get the time it takes to reach the maximum height

then twice of the time it takes to reach maximum height will be the time of flight

from newtons equation of motion

v=u+at

v=0

u=6m/s

0=6-9.81t

t=.61s

the time of flight will be 1.22secs

how far it travels will then be d, the basketball player moves with a horizontal speed 2.5m/s towards the ball

distance=speed*time

distance=2.5m/s*1.22

distance=6.11m