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17 June, 15:42

A rectangular loop of wire with width 0.4 cm and length 0.4 cm is oriented with the normal to the face of the loop making an angle of 30° with respect to the direction of B. The B field has a magnitude of 0.77 T. Find the magnetic flux through the loop.

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Answers (2)
  1. 17 June, 17:31
    0
    1.07*10⁻⁵ Wb

    Explanation:

    Using

    Φ = BAcosθ ... Equation 1

    Where Φ = magnetic Flux, B = magnetic Field, A = Area of the rectangular loop, Angle between the loop and the Field.

    But

    A = L*W ... Equation 2

    Where L = Length, W = Width.

    Substitute equation 2 into equation 1

    Φ = BLWcosΦ ... Equation 3

    Given: B = 0.77 T, L = 0.4 cm = 0.004 m, W = 0.4 cm = 0.004 m, Ф = 30°

    Substitute into equation 3

    Ф = 0.77 (0.004) (0.004) cos30

    Ф = 1.07*10⁻⁵ Wb.

    Hence the magnetic Field through the loop = 1.07*10⁻⁵ Wb.
  2. 17 June, 19:40
    0
    0.001067 Wb

    Explanation:

    Parameters given:

    Magnetic field, B = 0.77 T

    Angle, θ = 30º

    Width = 0.4cm = 0.04m

    Length = 0.4cm = 0.04m

    Magnetic flux, Φ (B) is given as:

    Φ (B) = B * A * cosθ

    Where A is Area

    Area = length * width = 0.04 * 0.04 = 0.0016 m²

    Φ (B) = 0.77 * 0.0016 * cos30

    Φ (B) = 0.00167 Wb
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