Two long straight wires enter a room through a window. One carries a current of 2.9A into the room, while the other carries a current of 4.4 out of the room. Calculate the magnitude (in T. m) of the path integral of B. ds around the window frame.

Answer and Explanation:

curents i = 2.9 A

i ' = 4.4 A

the magnitude (in T. m) of the path integral of B. dl around the window frame = μo * current enclosed

= μo * (i ' - i)

Since from Ampere's law

where μ o = permeability of free space = 4π * 10 ^-7 H / m

plug the values we get the magnitude (in T. m) of the path integral of B. dl = (4π*10^-7) (2.9+4.4)

= 1.884 * 10^-6 Tm