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10 August, 03:10

Two pans of a balance are 65.3 cm apart.

The fulcrum of the balance has been shifted

1.48 cm away from the center by a dishonest

shopkeeper.

By what percentage is the true weight of the

goods being marked up by the shopkeeper?

Assume the balance has negligible mass.

Answer in units of %.

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Answers (1)
  1. 10 August, 04:32
    0
    9.50%

    Explanation:

    Let's say m is the true weight and M is the weight of the counterweight.

    The original distance between the pans and the center is 65.3 cm / 2 = 32.65 cm. The fulcrum is then moved 1.48 cm towards the counterweight.

    Sum of the moments about the fulcrum:

    m (32.65 + 1.48) - M (32.65 - 1.48) = 0

    34.13 m - 31.17 M = 0

    34.13 m = 31.17 M

    M / m = 34.13 / 31.17

    M / m = 1.0950

    The true weight is being marked up by 9.50%.
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