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11 August, 11:36

If a second particle, with the same electric charge but ten times as massive, enters the field with the same velocity v ⃗, what is its period? View Available Hint (s) If a second particle, with the same electric charge but ten times as massive, enters the field with the same velocity, what is its period? T/10 T 5T 10T Submit Part B Complete previous part (s) Provide Feedback Next

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  1. 11 August, 13:17
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    When an moving electric charge passes through a uniform magnetic field

    its motion becomes circular.

    If m be the mass v be the velocity, q be the charge on the mass B be the magnetic field and R be the radius of circular path

    force on the moving charge created by magnetic field

    = B q v

    Centripetal force required for circular motion

    = m v² / R

    For balancing

    B q v = m v² / R

    v = B q R / m

    Time period of rotation

    T = 2π R / v

    = 2 π R m / B q R

    = 2 π m / B q

    For first particle

    T₁ = 2 π m₁ / B q₁

    For second particle

    T₂ = 2 π m₂ / B q₂

    q₁ = q₂ and 10 m₁ = m₂ (given)

    Putting the values in second equation

    T₂ = 2 π 10 m₁ / B q₁

    = 10 x 2 π m₁ / B q₁

    = 10 T₁

    Given T₁ = T

    T₂ = 10 T
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