Ask Question
22 July, 00:24

When the pad is replaced by one that requires a distance of 4d to stop the same package, what happens to the length of time it takes for the package to stop?

+5
Answers (1)
  1. 22 July, 03:26
    0
    t = 4 t₁, We see that time is increased by a factor of 4

    Explanation:

    For this exercise let's use the concepts of kinematics

    v² = v₀² + 2 a d

    With the first pad when the package stopped zero speed, let's look for acceleration

    0 = v₀² - 2 a₁ d

    a₁ = v₀² / 2 d

    Let's use the equation to enter time

    v = v₀ - a₁ t₁

    t₁ = v₀ / a₁

    When we replace the pad with another one where the distance is 4d

    a = v₀² / 2 (4d)

    a = a₁ / 4

    We see that the acceleration is 4 times lower.

    The equation kinematics

    v = v₀ - at

    t = v₀ / a

    We replace the acceleration

    t = v₀ 4/a1

    t = t₁ 4

    We see that time is increased by a factor of 4
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “When the pad is replaced by one that requires a distance of 4d to stop the same package, what happens to the length of time it takes for ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers