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15 June, 13:53

A solid wood door, 90.0 cm wide by 2.00 m tall has a mass of 35.0 kg. It is open and at rest. A small 500-g ball is thrown perpendicular to the door with a speed of 20.0 m/s and hits the door 60.0 cm from the hinged side. The ball rebounds with a speed of 16.0 m/s along the same line. What is the angular speed of the door just after the collision with the ball?

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  1. 15 June, 14:25
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    w = 1.14 rad/s

    Explanation:

    Moment of inertia ()

    Moment of inertia = 35 * 0.9^2 / 3 = 9.45 kg m^2

    Impulse ("An impulse is equal to the net force on the object times the time period over which this force is applied. ")

    Impulse = 0.5 * [16 - ( - 20) ]

    Impulse = 18 kg m/s

    angular momentum = M of I * angular speed w

    = 9.45 w

    = impulse * distance

    = 18 * 0.6

    9.45 w = 18 * 0.6

    w = 1.14 rad/s
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