A cylindrical specimen of brass that has a diam - eter of 20 mm, a tensile modulus of 110 GPa, and a Poisson's ratio of 0.35 is pulled in tension with force of 40,000 N. If the deformation is totally elas - tic, what is the strain experienced by the specimen?

strain = 0.0011575

Explanation:

Given:

- The diameter of specimen d = 0.02 m

- Applied uni-axial force P = 40,000 N

- Modulus of Elasticity E = 110 GPa

Find:

If the deformation is totally elastic, what is the strain experienced by the specimen?

Solution:

- First we need to calculate the stress in the specimen using the relation:

stress = Force / Area

stress = 40,000*4 / pi*d^2

stress = 160,000 / pi*0.02^2

stress = 127.323 MPa

- Now compute Elastic strain from the definition of Elastic modulus of a material:

E = stress / strain

strain = stress / E

- Plug in the values:

strain = 127.323 / 110*10^3

strain = 0.0011575