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5 August, 02:09

A single water molecule were oriented such that its dipole moment (magnitude 6.186 * 10 - 30 Cm is along a z axis. How much torque does an 8500 N/C electric field exert on the dipole if the field lies in x z - plane, 42 ∘ above the x - axis?

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  1. 5 August, 05:02
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    Torque=6.261*10^-43Nm

    Explanation:

    Torque is given by:

    Torque=dqEsin (phi)

    Where E is a constant=1.6022*10^-19

    d = distance = 6.186*10^-30cm

    Changing to metres=6.186*10^-28m

    q = the charge=8500NC

    Phi = 42°

    Torque = (6.186*10^-28) * 8500 * (1.6022*10^-19) sin42°

    Torque = 8.425*10^-43 * 0.7431

    Torque = 6.261 * 10^-43
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