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6 July, 18:51

The mass of a regulation tennis ball is 57 g. The ball is in contact with the tennis racket for 30 ms. The ball was served at 73.14 m/s. If the opponent returned the serve with a speed of 55 m/s, what force did he exert on the ball, assuming only horizontal motion?

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  1. 6 July, 21:47
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    Correct answer: F₂ = 104.5 N

    Explanation:

    Given:

    m = 57 g = 57 · 10⁻³ kg

    Δt = 30 ms = 30 · 10 ⁻³ seconds

    V₁ = 73.14 m/s service speed

    V₂ = 55 m/s returned speed

    M = m · V Momentum or Impulse

    You forgot to indicate what time the ball contact when returning.

    We will assume that the time is the same Δt = 30 ms = 30 10 ⁻³ seconds.

    The formula for calculating force is according to Newton's second law is:

    F = ΔM / Δt = m · ΔV / Δt

    Force during service is:

    F₁ = 57 · 10⁻³ · 73.14 / 30 · 10 ⁻³ = 138.97 N

    F₁ = 138.97 N

    Returned force:

    F₂ = 57 · 10⁻³ · 55 / 30 · 10 ⁻³ = 104.5 N

    F₂ = 104.5 N

    God is with you!
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