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14 January, 16:16

A hill that has a 36.1% grade is one that rises 36.1 m vertically for every 100.0 ml of distance in the horizontal direction. At what angle is such a hill inclined above the horizontal?

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  1. 14 January, 19:30
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    angle is 19.85°

    Explanation:

    given data

    grade = 36.1 %

    vertically distance y = 36.1 m

    horizontal distance x = 100 m

    to find out

    angle

    solution

    we know that according to question here

    it make a triangle shape that contain 100 m base and height 36.1 m

    and make angle with base is θ

    so by triangle we know here

    tanθ = y/x ... 1

    so we now put x and y and find θ

    tanθ = 36.1 / 100

    tanθ = 0.361

    θ = 19.85°

    so angle is 19.85°
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