A truck accelerates at 4.7 m/s for 150 m, reaching a final velocity of 47 m/s. What was it's initial velocity?

We can use option C

Initial velocity=28.3m/s

Explanation:

acceleration (a) = 4.7m/s^2

distance (d) = 150m

Final velocity (v) = 47m/s

Initial velocity (u) = ?

V^2=u^2+2xaxd

47^2=u^2+2x4.7x150

2209=u^2+1410

U^2=2209-1410

U^2=799

U=√ (799)

u=28.3m/s