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1 August, 10:16

Cross section of a solid circular rod is subject to a torque of t = 2.7 kn⋅m. if the diameter of the rod is d = 8 cm, what is the maximum shear stress?

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  1. 1 August, 11:20
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    Shear Stress = Force along the tangent / Area

    = 2700/π*r^2

    =2700/3.14*16

    =54
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