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14 November, 15:13

A car is traveling at 42.0 km/h on a flat highway. (a) If the coefficient of friction between road and tires on a rainy day is 0.107, what is the minimum distance in which the car will stop?

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  1. 14 November, 16:02
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    64.85 m

    Explanation:

    a)

    μ = Coefficient of friction between road and tire on rainy day = 0.107

    g = acceleration due to gravity = 9.8 m/s²

    a = acceleration experienced by car due to friction = - μg = - (0.107) (9.8) = - 1.05 m/s²

    v₀ = initial velocity of the car = 42 km/h = 11.67 m/s

    v = final speed of the car = 0 m/s

    d = minimum distance traveled before stopping

    Using the equation

    v² = v₀² + 2 a d

    0² = 11.67² + 2 ( - 1.05) d

    d = 64.85 m
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