The crossbar of a goal post on a professional American football field sits at a height of 3.05 meters (10 feet) above the field. A football is placed on the ground at midfield so that it is 54.9 meters (60 yards) horizontally from the position of the crossbar. The ball is then kicked so that its initial velocity is 26.0 m/s (58.2 mph) at an angle of 35 degrees above the horizontal. Neglecting air friction, does the ball make it over the goal post and by how much?

A. Yes, the ball passes 2.83 meters above the crossbar

B. No, the ball passes 1.57 meters below the crossbar

C. No, the ball hits the ground before it reaches the crossbar

D No, the ball hits the crossbar

E. Yes, the ball passes 8.22 meters above the crossbar

Question

Physics

Caleb Garrison

27 April, 19:59

The crossbar of a goal post on a professional American football field sits at a height of 3.05 meters (10 feet) above the field. A football is placed on the ground at midfield so that it is 54.9 meters (60 yards) horizontally from the position of the crossbar. The ball is then kicked so that its initial velocity is 26.0 m/s (58.2 mph) at an angle of 35 degrees above the horizontal. Neglecting air friction, does the ball make it over the goal post and by how much?

A. Yes, the ball passes 2.83 meters above the crossbar

B. No, the ball passes 1.57 meters below the crossbar

C. No, the ball hits the ground before it reaches the crossbar

D No, the ball hits the crossbar

E. Yes, the ball passes 8.22 meters above the crossbar

+5

Answers (1)

Know the Answer?

Emmanuel Rowe · Answer 1

A. Yes, the ball passes 2.83 meters above the crossbar

Explanation:

This problem relates to projectile motion.

Horizontal component of velocity of ball = 26 cos 35 = 21.3 m / s

Vertical component of velocity = 26 sin35 = 14.9 m / s

Time to cover horizontal distance of goal post that is 54.9 m

= distance / horizontal speed

= 54.9 / 21.3

= 2.577 s.

vertical distance covered in this time

h = ut - 1/2 gt², u is vertical component of velocity, t = 2.577 s

h = 14.9 x 2.577 -.5 x 9.8 x 2.577²

= 38.39 - 32.54

= 5.85 m

So the ball crosses the crossbar above it by 5.85 - 3.05 = 2.8 m