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4 May, 23:46

A horizontal force of 750 N is needed to overcome the force of static friction between a level floor and a 250-kg crate. If g-9.8 m/s, what is the coefficient of static friction? a. 3.0 b. 0.15 c. 0.28 d. 0.31

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  1. 5 May, 03:26
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    0.31

    Explanation:

    horizontal force, F = 750 N

    mass of crate, m = 250 kg

    g = 9.8 m/s^2

    The friction force becomes applied force = 750 N

    According to the laws of friction,

    Friction force = μ x Normal reaction of the surface

    here, μ be the coefficient of friction

    750 = μ x m g

    750 = μ x 250 x 9.8

    μ = 0.31

    Thus, the coefficient of static friction is 0.31.
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